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(4x)(x+63)=180
We move all terms to the left:
(4x)(x+63)-(180)=0
We multiply parentheses
4x^2+252x-180=0
a = 4; b = 252; c = -180;
Δ = b2-4ac
Δ = 2522-4·4·(-180)
Δ = 66384
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{66384}=\sqrt{144*461}=\sqrt{144}*\sqrt{461}=12\sqrt{461}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(252)-12\sqrt{461}}{2*4}=\frac{-252-12\sqrt{461}}{8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(252)+12\sqrt{461}}{2*4}=\frac{-252+12\sqrt{461}}{8} $
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