(4w-7)(8-w)=0

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Solution for (4w-7)(8-w)=0 equation:



(4w-7)(8-w)=0
We add all the numbers together, and all the variables
(4w-7)(-1w+8)=0
We multiply parentheses ..
(-4w^2+32w+7w-56)=0
We get rid of parentheses
-4w^2+32w+7w-56=0
We add all the numbers together, and all the variables
-4w^2+39w-56=0
a = -4; b = 39; c = -56;
Δ = b2-4ac
Δ = 392-4·(-4)·(-56)
Δ = 625
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{625}=25$
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(39)-25}{2*-4}=\frac{-64}{-8} =+8 $
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(39)+25}{2*-4}=\frac{-14}{-8} =1+3/4 $

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