(4w-3)w=594

Solution for (4w-3)w=594 equation:

(4w-3)w=594

We move all terms to the left:

(4w-3)w-(594)=0

We multiply parentheses

4w^2-3w-594=0

a = 4; b = -3; c = -594;
Δ = b2-4ac
Δ = -32-4·4·(-594)
Δ = 9513
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{9513}=\sqrt{9*1057}=\sqrt{9}*\sqrt{1057}=3\sqrt{1057}$
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-3)-3\sqrt{1057}}{2*4}=\frac{3-3\sqrt{1057}}{8}
$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-3)+3\sqrt{1057}}{2*4}=\frac{3+3\sqrt{1057}}{8}
$