(4w+2)-(2w-7)=(6w+5)+(7w-4)

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Solution for (4w+2)-(2w-7)=(6w+5)+(7w-4) equation: 



(4w+2)-(2w-7)=(6w+5)+(7w-4)

We move all terms to the left:

(4w+2)-(2w-7)-((6w+5)+(7w-4))=0

We get rid of parentheses

4w-2w-((6w+5)+(7w-4))+2+7=0



We calculate terms in parentheses: -((6w+5)+(7w-4)), so:

(6w+5)+(7w-4)

We get rid of parentheses

6w+7w+5-4

We add all the numbers together, and all the variables

13w+1

Back to the equation:

-(13w+1)



We add all the numbers together, and all the variables

2w-(13w+1)+9=0

We get rid of parentheses

2w-13w-1+9=0

We add all the numbers together, and all the variables

-11w+8=0

We move all terms containing w to the left, all other terms to the right

-11w=-8

w=-8/-11

w=8/11

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