(4v-3)v=5

Solution for (4v-3)v=5 equation:

(4v-3)v=5

We move all terms to the left:

(4v-3)v-(5)=0

We multiply parentheses

4v^2-3v-5=0

a = 4; b = -3; c = -5;
Δ = b2-4ac
Δ = -32-4·4·(-5)
Δ = 89
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-3)-\sqrt{89}}{2*4}=\frac{3-\sqrt{89}}{8}
$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-3)+\sqrt{89}}{2*4}=\frac{3+\sqrt{89}}{8}
$