(4v-1)(3-v)=0

Solution for (4v-1)(3-v)=0 equation:

(4v-1)(3-v)=0

We add all the numbers together, and all the variables

(4v-1)(-1v+3)=0

We multiply parentheses ..

(-4v^2+12v+v-3)=0

We get rid of parentheses

-4v^2+12v+v-3=0

We add all the numbers together, and all the variables

-4v^2+13v-3=0

a = -4; b = 13; c = -3;
Δ = b2-4ac
Δ = 132-4·(-4)·(-3)
Δ = 121
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{121}=11$
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(13)-11}{2*-4}=\frac{-24}{-8}
=+3
$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(13)+11}{2*-4}=\frac{-2}{-8}
=1/4
$