(4v+6)(9+v)=0

Solution for (4v+6)(9+v)=0 equation:

(4v+6)(9+v)=0

We add all the numbers together, and all the variables

(4v+6)(v+9)=0

We multiply parentheses ..

(+4v^2+36v+6v+54)=0

We get rid of parentheses

4v^2+36v+6v+54=0

We add all the numbers together, and all the variables

4v^2+42v+54=0

a = 4; b = 42; c = +54;
Δ = b2-4ac
Δ = 422-4·4·54
Δ = 900
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{900}=30$
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(42)-30}{2*4}=\frac{-72}{8}
=-9
$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(42)+30}{2*4}=\frac{-12}{8}
=-1+1/2
$