(4u+5)(3+u)=0

Solution for (4u+5)(3+u)=0 equation:

Simplifying
(4u + 5)(3 + u) = 0

Reorder the terms:
(5 + 4u)(3 + u) = 0

Multiply (5 + 4u) * (3 + u)
(5(3 + u) + 4u * (3 + u)) = 0
((3 * 5 + u * 5) + 4u * (3 + u)) = 0
((15 + 5u) + 4u * (3 + u)) = 0
(15 + 5u + (3 * 4u + u * 4u)) = 0
(15 + 5u + (12u + 4u2)) = 0

Combine like terms: 5u + 12u = 17u
(15 + 17u + 4u2) = 0

Solving
15 + 17u + 4u2 = 0

Solving for variable 'u'.

Factor a trinomial.
(3 + u)(5 + 4u) = 0

Subproblem 1
Set the factor '(3 + u)' equal to zero and attempt to solve:

Simplifying
3 + u = 0

Solving
3 + u = 0

Move all terms containing u to the left, all other terms to the right.

Add '-3' to each side of the equation.
3 + -3 + u = 0 + -3

Combine like terms: 3 + -3 = 0
0 + u = 0 + -3
u = 0 + -3

Combine like terms: 0 + -3 = -3
u = -3

Simplifying
u = -3
Subproblem 2
Set the factor '(5 + 4u)' equal to zero and attempt to solve:

Simplifying
5 + 4u = 0

Solving
5 + 4u = 0

Move all terms containing u to the left, all other terms to the right.

Add '-5' to each side of the equation.
5 + -5 + 4u = 0 + -5

Combine like terms: 5 + -5 = 0
0 + 4u = 0 + -5
4u = 0 + -5

Combine like terms: 0 + -5 = -5
4u = -5

Divide each side by '4'.
u = -1.25

Simplifying
u = -1.25
Solution
u = {-3, -1.25}