(4t-3)=2(t+1)+2

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Solution for (4t-3)=2(t+1)+2 equation:


Simplifying
(4t + -3) = 2(t + 1) + 2

Reorder the terms:
(-3 + 4t) = 2(t + 1) + 2

Remove parenthesis around (-3 + 4t)
-3 + 4t = 2(t + 1) + 2

Reorder the terms:
-3 + 4t = 2(1 + t) + 2
-3 + 4t = (1 * 2 + t * 2) + 2
-3 + 4t = (2 + 2t) + 2

Reorder the terms:
-3 + 4t = 2 + 2 + 2t

Combine like terms: 2 + 2 = 4
-3 + 4t = 4 + 2t

Solving
-3 + 4t = 4 + 2t

Solving for variable 't'.

Move all terms containing t to the left, all other terms to the right.

Add '-2t' to each side of the equation.
-3 + 4t + -2t = 4 + 2t + -2t

Combine like terms: 4t + -2t = 2t
-3 + 2t = 4 + 2t + -2t

Combine like terms: 2t + -2t = 0
-3 + 2t = 4 + 0
-3 + 2t = 4

Add '3' to each side of the equation.
-3 + 3 + 2t = 4 + 3

Combine like terms: -3 + 3 = 0
0 + 2t = 4 + 3
2t = 4 + 3

Combine like terms: 4 + 3 = 7
2t = 7

Divide each side by '2'.
t = 3.5

Simplifying
t = 3.5

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