(4s+2)(4s+2)=0

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Solution for (4s+2)(4s+2)=0 equation: 



(4s+2)(4s+2)=0

We multiply parentheses ..

(+16s^2+8s+8s+4)=0

We get rid of parentheses

16s^2+8s+8s+4=0

We add all the numbers together, and all the variables

16s^2+16s+4=0

a = 16; b = 16; c = +4;
Δ = b2-4ac
Δ = 162-4·16·4
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$s=\frac{-b}{2a}=\frac{-16}{32}=-1/2$

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