(4n-7)(11n+3)=0

Solution for (4n-7)(11n+3)=0 equation:

(4n-7)(11n+3)=0

We multiply parentheses ..

(+44n^2+12n-77n-21)=0

We get rid of parentheses

44n^2+12n-77n-21=0

We add all the numbers together, and all the variables

44n^2-65n-21=0

a = 44; b = -65; c = -21;
Δ = b2-4ac
Δ = -652-4·44·(-21)
Δ = 7921
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{7921}=89$
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-65)-89}{2*44}=\frac{-24}{88}
=-3/11
$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-65)+89}{2*44}=\frac{154}{88}
=1+3/4
$