(4n-62)=(2n+8)

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Solution for (4n-62)=(2n+8) equation: 



(4n-62)=(2n+8)

We move all terms to the left:

(4n-62)-((2n+8))=0

We get rid of parentheses

4n-((2n+8))-62=0



We calculate terms in parentheses: -((2n+8)), so:

(2n+8)

We get rid of parentheses

2n+8

Back to the equation:

-(2n+8)



We get rid of parentheses

4n-2n-8-62=0

We add all the numbers together, and all the variables

2n-70=0

We move all terms containing n to the left, all other terms to the right

2n=70

n=70/2

n=35

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