(4n-37)/3=10/n

Solution for (4n-37)/3=10/n equation:

D( n )

n = 0

n = 0

n = 0

n in (-oo:0) U (0:+oo)

(4*n-37)/3 = 10/n // - 10/n

(4*n-37)/3-(10/n) = 0

(4*n-37)/3-10*n^-1 = 0

(4*n-37)/3-10/n = 0

(n*(4*n-37))/(3*n)+(-10*3)/(3*n) = 0

n*(4*n-37)-10*3 = 0

4*n^2-37*n-30 = 0

4*n^2-37*n-30 = 0

4*n^2-37*n-30 = 0

DELTA = (-37)^2-(-30*4*4)

DELTA = 1849

DELTA > 0

n = (1849^(1/2)+37)/(2*4) or n = (37-1849^(1/2))/(2*4)

n = 10 or n = -3/4

(n+3/4)*(n-10) = 0

((n+3/4)*(n-10))/(3*n) = 0

((n+3/4)*(n-10))/(3*n) = 0 // * 3*n

(n+3/4)*(n-10) = 0

( n+3/4 )

n+3/4 = 0 // - 3/4

n = -3/4

( n-10 )

n-10 = 0 // + 10

n = 10

n in { -3/4, 10 }