(4n-28/3)=2n

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Solution for (4n-28/3)=2n equation:



(4n-28/3)=2n
We move all terms to the left:
(4n-28/3)-(2n)=0
We add all the numbers together, and all the variables
(+4n-28/3)-2n=0
We add all the numbers together, and all the variables
-2n+(+4n-28/3)=0
We get rid of parentheses
-2n+4n-28/3=0
We multiply all the terms by the denominator
-2n*3+4n*3-28=0
Wy multiply elements
-6n+12n-28=0
We add all the numbers together, and all the variables
6n-28=0
We move all terms containing n to the left, all other terms to the right
6n=28
n=28/6
n=4+2/3

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