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(4n+6)(2n+60)=180
We move all terms to the left:
(4n+6)(2n+60)-(180)=0
We multiply parentheses ..
(+8n^2+240n+12n+360)-180=0
We get rid of parentheses
8n^2+240n+12n+360-180=0
We add all the numbers together, and all the variables
8n^2+252n+180=0
a = 8; b = 252; c = +180;
Δ = b2-4ac
Δ = 2522-4·8·180
Δ = 57744
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{57744}=\sqrt{144*401}=\sqrt{144}*\sqrt{401}=12\sqrt{401}$$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(252)-12\sqrt{401}}{2*8}=\frac{-252-12\sqrt{401}}{16} $$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(252)+12\sqrt{401}}{2*8}=\frac{-252+12\sqrt{401}}{16} $
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