(4n+2)=2(2n-1)

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Solution for (4n+2)=2(2n-1) equation: 



(4n+2)=2(2n-1)

We move all terms to the left:

(4n+2)-(2(2n-1))=0

We get rid of parentheses

4n-(2(2n-1))+2=0



We calculate terms in parentheses: -(2(2n-1)), so:

2(2n-1)

We multiply parentheses

4n-2

Back to the equation:

-(4n-2)



We get rid of parentheses

4n-4n+2+2=0

We add all the numbers together, and all the variables

4!=0

There is no solution for this equation

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