(4m-7)(4m=7)

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Solution for (4m-7)(4m=7) equation: 



(4m-7)(4m=7)

We move all terms to the left:

(4m-7)(4m-(7))=0

We multiply parentheses ..

(+16m^2-28m-28m+49)=0

We get rid of parentheses

16m^2-28m-28m+49=0

We add all the numbers together, and all the variables

16m^2-56m+49=0

a = 16; b = -56; c = +49;
Δ = b2-4ac
Δ = -562-4·16·49
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$m=\frac{-b}{2a}=\frac{56}{32}=1+3/4$

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