(4m-6)/6=(2m+5)/7

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Solution for (4m-6)/6=(2m+5)/7 equation: 



(4m-6)/6=(2m+5)/7

We move all terms to the left:

(4m-6)/6-((2m+5)/7)=0

We calculate fractions


4m/()+(-((2m+5)*6)/()=0



We calculate terms in parentheses: +(-((2m+5)*6)/(), so:

-((2m+5)*6)/(

We multiply all the terms by the denominator


-((2m+5)*6)



We calculate terms in parentheses: -((2m+5)*6), so:

(2m+5)*6

We multiply parentheses

12m+30

Back to the equation:

-(12m+30)



We get rid of parentheses

-12m-30

Back to the equation:

+(-12m-30)



We get rid of parentheses

4m/()-12m-30=0

We multiply all the terms by the denominator


4m-12m*()-30*()=0

We add all the numbers together, and all the variables

4m-12m*()=0

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