(4m+1)(m+2)=

Solution for (4m+1)(m+2)= equation:

Simplifying
(4m + 1)(m + 2) = 0

Reorder the terms:
(1 + 4m)(m + 2) = 0

Reorder the terms:
(1 + 4m)(2 + m) = 0

Multiply (1 + 4m) * (2 + m)
(1(2 + m) + 4m * (2 + m)) = 0
((2 * 1 + m * 1) + 4m * (2 + m)) = 0
((2 + 1m) + 4m * (2 + m)) = 0
(2 + 1m + (2 * 4m + m * 4m)) = 0
(2 + 1m + (8m + 4m2)) = 0

Combine like terms: 1m + 8m = 9m
(2 + 9m + 4m2) = 0

Solving
2 + 9m + 4m2 = 0

Solving for variable 'm'.

Factor a trinomial.
(2 + m)(1 + 4m) = 0

Subproblem 1
Set the factor '(2 + m)' equal to zero and attempt to solve:

Simplifying
2 + m = 0

Solving
2 + m = 0

Move all terms containing m to the left, all other terms to the right.

Add '-2' to each side of the equation.
2 + -2 + m = 0 + -2

Combine like terms: 2 + -2 = 0
0 + m = 0 + -2
m = 0 + -2

Combine like terms: 0 + -2 = -2
m = -2

Simplifying
m = -2
Subproblem 2
Set the factor '(1 + 4m)' equal to zero and attempt to solve:

Simplifying
1 + 4m = 0

Solving
1 + 4m = 0

Move all terms containing m to the left, all other terms to the right.

Add '-1' to each side of the equation.
1 + -1 + 4m = 0 + -1

Combine like terms: 1 + -1 = 0
0 + 4m = 0 + -1
4m = 0 + -1

Combine like terms: 0 + -1 = -1
4m = -1

Divide each side by '4'.
m = -0.25

Simplifying
m = -0.25
Solution
m = {-2, -0.25}