(4j+1)-6(j+2)=

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Solution for (4j+1)-6(j+2)= equation:


Simplifying
(4j + 1) + -6(j + 2) = 0

Reorder the terms:
(1 + 4j) + -6(j + 2) = 0

Remove parenthesis around (1 + 4j)
1 + 4j + -6(j + 2) = 0

Reorder the terms:
1 + 4j + -6(2 + j) = 0
1 + 4j + (2 * -6 + j * -6) = 0
1 + 4j + (-12 + -6j) = 0

Reorder the terms:
1 + -12 + 4j + -6j = 0

Combine like terms: 1 + -12 = -11
-11 + 4j + -6j = 0

Combine like terms: 4j + -6j = -2j
-11 + -2j = 0

Solving
-11 + -2j = 0

Solving for variable 'j'.

Move all terms containing j to the left, all other terms to the right.

Add '11' to each side of the equation.
-11 + 11 + -2j = 0 + 11

Combine like terms: -11 + 11 = 0
0 + -2j = 0 + 11
-2j = 0 + 11

Combine like terms: 0 + 11 = 11
-2j = 11

Divide each side by '-2'.
j = -5.5

Simplifying
j = -5.5

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