(4j+-4)(j+1)=

Solution for (4j+-4)(j+1)= equation:

Simplifying
(4j + -4)(j + 1) = 0

Reorder the terms:
(-4 + 4j)(j + 1) = 0

Reorder the terms:
(-4 + 4j)(1 + j) = 0

Multiply (-4 + 4j) * (1 + j)
(-4(1 + j) + 4j * (1 + j)) = 0
((1 * -4 + j * -4) + 4j * (1 + j)) = 0
((-4 + -4j) + 4j * (1 + j)) = 0
(-4 + -4j + (1 * 4j + j * 4j)) = 0
(-4 + -4j + (4j + 4j2)) = 0

Combine like terms: -4j + 4j = 0
(-4 + 0 + 4j2) = 0
(-4 + 4j2) = 0

Solving
-4 + 4j2 = 0

Solving for variable 'j'.

Move all terms containing j to the left, all other terms to the right.

Add '4' to each side of the equation.
-4 + 4 + 4j2 = 0 + 4

Combine like terms: -4 + 4 = 0
0 + 4j2 = 0 + 4
4j2 = 0 + 4

Combine like terms: 0 + 4 = 4
4j2 = 4

Divide each side by '4'.
j2 = 1

Simplifying
j2 = 1

Take the square root of each side:
j = {-1, 1}