(4f+5)=2(5f+40)=180

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Solution for (4f+5)=2(5f+40)=180 equation: 



(4f+5)=2(5f+40)=180

We move all terms to the left:

(4f+5)-(2(5f+40))=0

We get rid of parentheses

4f-(2(5f+40))+5=0



We calculate terms in parentheses: -(2(5f+40)), so:

2(5f+40)

We multiply parentheses

10f+80

Back to the equation:

-(10f+80)



We get rid of parentheses

4f-10f-80+5=0

We add all the numbers together, and all the variables

-6f-75=0

We move all terms containing f to the left, all other terms to the right

-6f=75

f=75/-6

f=-12+1/2

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