(4d-2c)(2d+c)=

Solution for (4d-2c)(2d+c)= equation:

Simplifying
(4d + -2c)(2d + c) = 0

Reorder the terms:
(-2c + 4d)(2d + c) = 0

Reorder the terms:
(-2c + 4d)(c + 2d) = 0

Multiply (-2c + 4d) * (c + 2d)
(-2c * (c + 2d) + 4d * (c + 2d)) = 0
((c * -2c + 2d * -2c) + 4d * (c + 2d)) = 0

Reorder the terms:
((-4cd + -2c2) + 4d * (c + 2d)) = 0
((-4cd + -2c2) + 4d * (c + 2d)) = 0
(-4cd + -2c2 + (c * 4d + 2d * 4d)) = 0
(-4cd + -2c2 + (4cd + 8d2)) = 0

Reorder the terms:
(-4cd + 4cd + -2c2 + 8d2) = 0

Combine like terms: -4cd + 4cd = 0
(0 + -2c2 + 8d2) = 0
(-2c2 + 8d2) = 0

Solving
-2c2 + 8d2 = 0

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-8d2' to each side of the equation.
-2c2 + 8d2 + -8d2 = 0 + -8d2

Combine like terms: 8d2 + -8d2 = 0
-2c2 + 0 = 0 + -8d2
-2c2 = 0 + -8d2
Remove the zero:
-2c2 = -8d2

Divide each side by '-2'.
c2 = 4d2

Simplifying
c2 = 4d2

Take the square root of each side:
c = {-2d, 2d}