(4c+5)/3=(2c+4)/5

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Solution for (4c+5)/3=(2c+4)/5 equation: 



(4c+5)/3=(2c+4)/5

We move all terms to the left:

(4c+5)/3-((2c+4)/5)=0

We calculate fractions


4c/()+(-((2c+4)*3)/()=0



We calculate terms in parentheses: +(-((2c+4)*3)/(), so:

-((2c+4)*3)/(

We multiply all the terms by the denominator


-((2c+4)*3)



We calculate terms in parentheses: -((2c+4)*3), so:

(2c+4)*3

We multiply parentheses

6c+12

Back to the equation:

-(6c+12)



We get rid of parentheses

-6c-12

Back to the equation:

+(-6c-12)



We get rid of parentheses

4c/()-6c-12=0

We multiply all the terms by the denominator


4c-6c*()-12*()=0

We add all the numbers together, and all the variables

4c-6c*()=0

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