(4c+1)6c-5c=28c

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Solution for (4c+1)6c-5c=28c equation:


Simplifying
(4c + 1) * 6c + -5c = 28c

Reorder the terms:
(1 + 4c) * 6c + -5c = 28c

Reorder the terms for easier multiplication:
6c(1 + 4c) + -5c = 28c
(1 * 6c + 4c * 6c) + -5c = 28c
(6c + 24c2) + -5c = 28c

Reorder the terms:
6c + -5c + 24c2 = 28c

Combine like terms: 6c + -5c = 1c
1c + 24c2 = 28c

Solving
1c + 24c2 = 28c

Solving for variable 'c'.

Reorder the terms:
1c + -28c + 24c2 = 28c + -28c

Combine like terms: 1c + -28c = -27c
-27c + 24c2 = 28c + -28c

Combine like terms: 28c + -28c = 0
-27c + 24c2 = 0

Factor out the Greatest Common Factor (GCF), '3c'.
3c(-9 + 8c) = 0

Ignore the factor 3.

Subproblem 1

Set the factor 'c' equal to zero and attempt to solve: Simplifying c = 0 Solving c = 0 Move all terms containing c to the left, all other terms to the right. Simplifying c = 0

Subproblem 2

Set the factor '(-9 + 8c)' equal to zero and attempt to solve: Simplifying -9 + 8c = 0 Solving -9 + 8c = 0 Move all terms containing c to the left, all other terms to the right. Add '9' to each side of the equation. -9 + 9 + 8c = 0 + 9 Combine like terms: -9 + 9 = 0 0 + 8c = 0 + 9 8c = 0 + 9 Combine like terms: 0 + 9 = 9 8c = 9 Divide each side by '8'. c = 1.125 Simplifying c = 1.125

Solution

c = {0, 1.125}

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