(4b-3)=(4b-3)=

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Solution for (4b-3)=(4b-3)= equation: 



(4b-3)=(4b-3)=

We move all terms to the left:

(4b-3)-((4b-3))=0

We get rid of parentheses

4b-((4b-3))-3=0



We calculate terms in parentheses: -((4b-3)), so:

(4b-3)

We get rid of parentheses

4b-3

Back to the equation:

-(4b-3)



We get rid of parentheses

4b-4b+3-3=0

We add all the numbers together, and all the variables

=0

b=0/1

b=0

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