(4b+2)+(2c+6)=

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Solution for (4b+2)+(2c+6)= equation:


Simplifying
(4b + 2) + (2c + 6) = 0

Reorder the terms:
(2 + 4b) + (2c + 6) = 0

Remove parenthesis around (2 + 4b)
2 + 4b + (2c + 6) = 0

Reorder the terms:
2 + 4b + (6 + 2c) = 0

Remove parenthesis around (6 + 2c)
2 + 4b + 6 + 2c = 0

Reorder the terms:
2 + 6 + 4b + 2c = 0

Combine like terms: 2 + 6 = 8
8 + 4b + 2c = 0

Solving
8 + 4b + 2c = 0

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Add '-8' to each side of the equation.
8 + 4b + -8 + 2c = 0 + -8

Reorder the terms:
8 + -8 + 4b + 2c = 0 + -8

Combine like terms: 8 + -8 = 0
0 + 4b + 2c = 0 + -8
4b + 2c = 0 + -8

Combine like terms: 0 + -8 = -8
4b + 2c = -8

Add '-2c' to each side of the equation.
4b + 2c + -2c = -8 + -2c

Combine like terms: 2c + -2c = 0
4b + 0 = -8 + -2c
4b = -8 + -2c

Divide each side by '4'.
b = -2 + -0.5c

Simplifying
b = -2 + -0.5c

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