(4a-9i)(2a+3bi)=

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Solution for (4a-9i)(2a+3bi)= equation: 


Simplifying
(4a + -9i)(2a + 3bi) = 0

Multiply (4a + -9i) * (2a + 3bi)
(4a * (2a + 3bi) + -9i * (2a + 3bi)) = 0
((2a * 4a + 3bi * 4a) + -9i * (2a + 3bi)) = 0

Reorder the terms:
((12abi + 8a2) + -9i * (2a + 3bi)) = 0
((12abi + 8a2) + -9i * (2a + 3bi)) = 0
(12abi + 8a2 + (2a * -9i + 3bi * -9i)) = 0
(12abi + 8a2 + (-18ai + -27bi2)) = 0

Reorder the terms:
(12abi + -18ai + 8a2 + -27bi2) = 0
(12abi + -18ai + 8a2 + -27bi2) = 0

Solving
12abi + -18ai + 8a2 + -27bi2 = 0

Solving for variable 'a'.

The solution to this equation could not be determined.

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