(4a-3b+2c)-(2a-3b+4c)=

Solution for (4a-3b+2c)-(2a-3b+4c)= equation:

Simplifying
(4a + -3b + 2c) + -1(2a + -3b + 4c) = 0

Remove parenthesis around (4a + -3b + 2c)
4a + -3b + 2c + -1(2a + -3b + 4c) = 0
4a + -3b + 2c + (2a * -1 + -3b * -1 + 4c * -1) = 0
4a + -3b + 2c + (-2a + 3b + -4c) = 0

Reorder the terms:
4a + -2a + -3b + 3b + 2c + -4c = 0

Combine like terms: 4a + -2a = 2a
2a + -3b + 3b + 2c + -4c = 0

Combine like terms: -3b + 3b = 0
2a + 0 + 2c + -4c = 0
2a + 2c + -4c = 0

Combine like terms: 2c + -4c = -2c
2a + -2c = 0

Solving
2a + -2c = 0

Solving for variable 'a'.

Move all terms containing a to the left, all other terms to the right.

Add '2c' to each side of the equation.
2a + -2c + 2c = 0 + 2c

Combine like terms: -2c + 2c = 0
2a + 0 = 0 + 2c
2a = 0 + 2c
Remove the zero:
2a = 2c

Divide each side by '2'.
a = c

Simplifying
a = c