(4a-3)(3a+4)=(2a-1)(6a+1)

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Solution for (4a-3)(3a+4)=(2a-1)(6a+1) equation: 



(4a-3)(3a+4)=(2a-1)(6a+1)

We move all terms to the left:

(4a-3)(3a+4)-((2a-1)(6a+1))=0

We multiply parentheses ..

(+12a^2+16a-9a-12)-((2a-1)(6a+1))=0



We calculate terms in parentheses: -((2a-1)(6a+1)), so:

(2a-1)(6a+1)

We multiply parentheses ..

(+12a^2+2a-6a-1)

We get rid of parentheses

12a^2+2a-6a-1

We add all the numbers together, and all the variables

12a^2-4a-1

Back to the equation:

-(12a^2-4a-1)



We get rid of parentheses

12a^2-12a^2+16a-9a+4a-12+1=0

We add all the numbers together, and all the variables

11a-11=0

We move all terms containing a to the left, all other terms to the right

11a=11

a=11/11

a=1

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