(4a+2(a+1))/6=4.33333

Solution for (4a+2(a+1))/6=4.33333 equation:

(4a+2(a+1))/6=4.33333

We move all terms to the left:

(4a+2(a+1))/6-(4.33333)=0

We add all the numbers together, and all the variables

(4a+2(a+1))/6-4.33333=0

We multiply all the terms by the denominator


(4a+2(a+1))-(4.33333)*6=0


We calculate terms in parentheses: +(4a+2(a+1)), so:

4a+2(a+1)

We multiply parentheses

4a+2a+2

We add all the numbers together, and all the variables

6a+2

Back to the equation:

+(6a+2)


We add all the numbers together, and all the variables

(6a+2)-25.99998=0

We get rid of parentheses

6a+2-25.99998=0

We add all the numbers together, and all the variables

6a-23.99998=0

We move all terms containing a to the left, all other terms to the right

6a=23.99998

a=23.99998/6

a=3+3.0000200002/3.0000300003