(48+2x)(72+2x)=0

Solution for (48+2x)(72+2x)=0 equation:

(48+2x)(72+2x)=0

We add all the numbers together, and all the variables

(2x+48)(2x+72)=0

We multiply parentheses ..

(+4x^2+144x+96x+3456)=0

We get rid of parentheses

4x^2+144x+96x+3456=0

We add all the numbers together, and all the variables

4x^2+240x+3456=0

a = 4; b = 240; c = +3456;
Δ = b2-4ac
Δ = 2402-4·4·3456
Δ = 2304
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2304}=48$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(240)-48}{2*4}=\frac{-288}{8}
=-36
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(240)+48}{2*4}=\frac{-192}{8}
=-24
$