(42+x)+(x-12)=36

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Solution for (42+x)+(x-12)=36 equation: 



(42+x)+(x-12)=36

We move all terms to the left:

(42+x)+(x-12)-(36)=0

We add all the numbers together, and all the variables

(x+42)+(x-12)-36=0

We get rid of parentheses

x+x+42-12-36=0

We add all the numbers together, and all the variables

2x-6=0

We move all terms containing x to the left, all other terms to the right

2x=6

x=6/2

x=3

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