(40000+(10000/4)x)(28-x)+(40000+(10000/4)x)(4.00)=0

Solution for (40000+(10000/4)x)(28-x)+(40000+(10000/4)x)(4.00)=0 equation:

(40000+(10000/4)x)(28-x)+(40000+(10000/4)x)(4.00)=0


Domain of the equation: 4)x)(28-x)!=0

x∈R



Domain of the equation: 4)x)(4.00)!=0

x∈R


We add all the numbers together, and all the variables

(40000+2500x)(-1x+28)+(40000+2500x)4=0

We multiply parentheses

(40000+2500x)(-1x+28)+10000x+160000=0

We multiply parentheses ..

(-40000x+1120000-2500x^2+70000x)+10000x+160000=0

We get rid of parentheses

-2500x^2-40000x+70000x+10000x+1120000+160000=0

We add all the numbers together, and all the variables

-2500x^2+40000x+1280000=0

a = -2500; b = 40000; c = +1280000;
Δ = b2-4ac
Δ = 400002-4·(-2500)·1280000
Δ = 14400000000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{14400000000}=120000$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(40000)-120000}{2*-2500}=\frac{-160000}{-5000}
=+32
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(40000)+120000}{2*-2500}=\frac{80000}{-5000}
=-16
$