(4/y+2)+(5/y-4)=(9/y+5)

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Solution for (4/y+2)+(5/y-4)=(9/y+5) equation: 


D( y )

y = 0

y = 0

y = 0

y in (-oo:0) U (0:+oo)

4/y+5/y-4+2 = 9/y+5 // - 9/y+5

4/y+5/y-(9/y)-5-4+2 = 0

4/y+5/y-9*y^-1-5-4+2 = 0

-7 = 0

y belongs to the empty set

y belongs to the empty set

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