(4/x-1)=(13/x+8)

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Solution for (4/x-1)=(13/x+8) equation:


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

4/x-1 = 13/x+8 // - 13/x+8

4/x-(13/x)-8-1 = 0

4/x-13*x^-1-8-1 = 0

-9*x^-1 = 9 // : -9

x^-1 = -1

-1 < 0

1/(x^1) = -1 // * x^1

1 = -1*x^1 // : -1

-1 = x^1

x = -1

x = -1

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