(4/9)x+(1/5)x=3.45

Solution for (4/9)x+(1/5)x=3.45 equation:

(4/9)x+(1/5)x=3.45

We move all terms to the left:

(4/9)x+(1/5)x-(3.45)=0


Domain of the equation: 9)x!=0

x!=0/1

x!=0

x∈R



Domain of the equation: 5)x!=0

x!=0/1

x!=0

x∈R


We add all the numbers together, and all the variables

(+4/9)x+(+1/5)x-(3.45)=0

We add all the numbers together, and all the variables

(+4/9)x+(+1/5)x-3.45=0

We multiply parentheses

4x^2+x^2-3.45=0

We add all the numbers together, and all the variables

5x^2-3.45=0

a = 5; b = 0; c = -3.45;
Δ = b2-4ac
Δ = 02-4·5·(-3.45)
Δ = 69
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{69}}{2*5}=\frac{0-\sqrt{69}}{10}
=-\frac{\sqrt{}}{10}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{69}}{2*5}=\frac{0+\sqrt{69}}{10}
=\frac{\sqrt{}}{10}
$