(4/7w)+(6/w)=1

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Solution for (4/7w)+(6/w)=1 equation: 


D( w )

w = 0

w = 0

w = 0

w in (-oo:0) U (0:+oo)

(4/7)*w+6/w = 1 // - 1

(4/7)*w+6/w-1 = 0

4/7*w^1+6*w^-1-1*w^0 = 0

(4/7*w^2-1*w^1+6*w^0)/(w^1) = 0 // * w^2

w^1*(4/7*w^2-1*w^1+6*w^0) = 0

w^1

(4/7)*w^2-w+6 = 0

(4/7)*w^2-w+6 = 0

DELTA = (-1)^2-(4*6*(4/7))

DELTA = -89/7

DELTA < 0

w in { } 

w belongs to the empty set

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