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(4/6)y-5=-1
We move all terms to the left:
(4/6)y-5-(-1)=0
Domain of the equation: 6)y!=0We add all the numbers together, and all the variables
y!=0/1
y!=0
y∈R
(+4/6)y-5-(-1)=0
We add all the numbers together, and all the variables
(+4/6)y-4=0
We multiply parentheses
4y^2-4=0
a = 4; b = 0; c = -4;
Δ = b2-4ac
Δ = 02-4·4·(-4)
Δ = 64
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{64}=8$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-8}{2*4}=\frac{-8}{8} =-1 $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+8}{2*4}=\frac{8}{8} =1 $
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