(4/3x)+25=35

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Solution for (4/3x)+25=35 equation: 



(4/3x)+25=35

We move all terms to the left:

(4/3x)+25-(35)=0



Domain of the equation: 3x)!=0

x!=0/1

x!=0

x∈R



We add all the numbers together, and all the variables

(+4/3x)+25-35=0

We add all the numbers together, and all the variables

(+4/3x)-10=0

We get rid of parentheses

4/3x-10=0

We multiply all the terms by the denominator


-10*3x+4=0

Wy multiply elements

-30x+4=0

We move all terms containing x to the left, all other terms to the right

-30x=-4

x=-4/-30

x=2/15

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