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(4/3)x=53
We move all terms to the left:
(4/3)x-(53)=0
Domain of the equation: 3)x!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
(+4/3)x-53=0
We multiply parentheses
4x^2-53=0
a = 4; b = 0; c = -53;
Δ = b2-4ac
Δ = 02-4·4·(-53)
Δ = 848
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{848}=\sqrt{16*53}=\sqrt{16}*\sqrt{53}=4\sqrt{53}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-4\sqrt{53}}{2*4}=\frac{0-4\sqrt{53}}{8} =-\frac{4\sqrt{53}}{8} =-\frac{\sqrt{53}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+4\sqrt{53}}{2*4}=\frac{0+4\sqrt{53}}{8} =\frac{4\sqrt{53}}{8} =\frac{\sqrt{53}}{2} $
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