(4/3)x-5/3=(1/3)x+10

Solution for (4/3)x-5/3=(1/3)x+10 equation:

(4/3)x-5/3=(1/3)x+10

We move all terms to the left:

(4/3)x-5/3-((1/3)x+10)=0


Domain of the equation: 3)x!=0

x!=0/1

x!=0

x∈R



Domain of the equation: 3)x+10)!=0

x!=0/1

x!=0

x∈R


We add all the numbers together, and all the variables

(+4/3)x-((+1/3)x+10)-5/3=0

We multiply parentheses

4x^2-((+1/3)x+10)-5/3=0

We calculate fractions


4x^2=0

a = 4; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·4·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{8}=0$