(4/3)x+4=1/5

Solution for (4/3)x+4=1/5 equation:

(4/3)x+4=1/5

We move all terms to the left:

(4/3)x+4-(1/5)=0


Domain of the equation: 3)x!=0

x!=0/1

x!=0

x∈R


We add all the numbers together, and all the variables

(+4/3)x+4-(+1/5)=0

We multiply parentheses

4x^2+4-(+1/5)=0

We get rid of parentheses

4x^2+4-1/5=0

We multiply all the terms by the denominator


4x^2*5-1+4*5=0

We add all the numbers together, and all the variables

4x^2*5+19=0

Wy multiply elements

20x^2+19=0

a = 20; b = 0; c = +19;
Δ = b2-4ac
Δ = 02-4·20·19
Δ = -1520
Delta is less than zero, so there is no solution for the equation