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(4/3)(3x-6)=16
We move all terms to the left:
(4/3)(3x-6)-(16)=0
Domain of the equation: 3)(3x-6)!=0We add all the numbers together, and all the variables
x∈R
(+4/3)(3x-6)-16=0
We multiply parentheses ..
(+12x^2+4/3*-6)-16=0
We multiply all the terms by the denominator
(+12x^2+4-16*3*-6)=0
We get rid of parentheses
12x^2+4-6-16*3*=0
We add all the numbers together, and all the variables
12x^2=0
a = 12; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·12·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$x=\frac{-b}{2a}=\frac{0}{24}=0$
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