(4/3(15-6y))-7=11

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Solution for (4/3(15-6y))-7=11 equation: 



(4/3(15-6y))-7=11

We move all terms to the left:

(4/3(15-6y))-7-(11)=0



Domain of the equation: 3(15-6y))!=0

y∈R



We add all the numbers together, and all the variables

(4/3(-6y+15))-7-11=0

We add all the numbers together, and all the variables

(4/3(-6y+15))-18=0

We multiply all the terms by the denominator


(4-18*3(-6y+15))=0



We calculate terms in parentheses: +(4-18*3(-6y+15)), so:

4-18*3(-6y+15)

determiningTheFunctionDomain
-18*3(-6y+15)+4

Wy multiply elements

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