(4/10)x-3x+(6/5)=(4/5)

Solution for (4/10)x-3x+(6/5)=(4/5) equation:

(4/10)x-3x+(6/5)=(4/5)

We move all terms to the left:

(4/10)x-3x+(6/5)-((4/5))=0


Domain of the equation: 10)x!=0

x!=0/1

x!=0

x∈R


We add all the numbers together, and all the variables

(+4/10)x-3x+(+6/5)-((+4/5))=0

We add all the numbers together, and all the variables

-3x+(+4/10)x+(+6/5)-((+4/5))=0

We multiply parentheses

4x^2-3x+(+6/5)-((+4/5))=0

We get rid of parentheses

4x^2-3x+6/5-((+4/5))=0

We calculate fractions


4x^2-3x=0

a = 4; b = -3; c = 0;
Δ = b2-4ac
Δ = -32-4·4·0
Δ = 9
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{9}=3$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-3)-3}{2*4}=\frac{0}{8}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-3)+3}{2*4}=\frac{6}{8}
=3/4
$