(4/(3x+1))-(18x/(3x-1))=-6

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Solution for (4/(3x+1))-(18x/(3x-1))=-6 equation: 



(4/(3x+1))-(18x/(3x-1))=-6

We move all terms to the left:

(4/(3x+1))-(18x/(3x-1))-(-6)=0



Domain of the equation: (3x+1))!=0

x∈R





Domain of the equation: (3x-1))!=0

x∈R



We add all the numbers together, and all the variables

(4/(3x+1))-(18x/(3x-1))+6=0

We calculate fractions


(-54x^2-18x)/((3x+1))*3x+(12x-4)/((3x+1))*3x+6=0

We multiply all the terms by the denominator


(-54x^2-18x)+(12x-4)+6*((3x+1))*3x=0

We get rid of parentheses

-54x^2-18x+12x+6*((3x+1))*3x-4=0

We add all the numbers together, and all the variables

-54x^2-6x+6*((3x+1))*3x-4=0

We move all terms containing x to the left, all other terms to the right

-54x^2-6x+6*((3x+1))*3x=4

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