(4/(3x+1))+(1/(2x-1))=9/5x

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Solution for (4/(3x+1))+(1/(2x-1))=9/5x equation: 



(4/(3x+1))+(1/(2x-1))=9/5x

We move all terms to the left:

(4/(3x+1))+(1/(2x-1))-(9/5x)=0



Domain of the equation: (3x+1))!=0

x∈R





Domain of the equation: (2x-1))!=0

x∈R





Domain of the equation: 5x)!=0

x!=0/1

x!=0

x∈R



We add all the numbers together, and all the variables

(4/(3x+1))+(1/(2x-1))-(+9/5x)=0

We get rid of parentheses

(4/(3x+1))+(1/(2x-1))-9/5x=0

We calculate fractions


((4*(2x-1))*5x)/((3x+1))*(2x-1))*5x)+((1*(3x+1))*5x)/((3x+1))*(2x-1))*5x)+(-9*(3x+1))*2x/((3x+1))*(2x-1))*5x)=0

We can not solve this equation

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