(4/(3(x-2)))-(2/(3x))=(1/(x=2))

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Solution for (4/(3(x-2)))-(2/(3x))=(1/(x=2)) equation: 



(4/(3(x-2)))-(2/(3x))=(1/(x=2))

We move all terms to the left:

(4/(3(x-2)))-(2/(3x))-((1/(x)=0



Domain of the equation: (3(x-2)))!=0

x∈R





Domain of the equation: 3x)!=0

x!=0/1

x!=0

x∈R





Domain of the equation: x!=0

x∈R



We add all the numbers together, and all the variables

(4/(3(x-2)))-(+2/3x)-((1/x=0

We get rid of parentheses

(4/(3(x-2)))-2/3x-((1/x=0

We calculate fractions


((4*3x*x)/((3(x-2)))*3x*x)+(-2*(3(x-2)))*x)/((3(x-2)))*3x*x)+(-((1*(3(x-2)))*3x)/((3(x-2)))*3x*x)=0



We calculate terms in parentheses: +((4*3x*x)/((3(x-2)))*3x*x), so:

(4*3x*x)/((3(x-2)))*3x*x

We add all the numbers together, and all the variables

(+4*3x*x)/((3(x-2)))*3x*x

We multiply all the terms by the denominator


(+4*3x*x)

We get rid of parentheses

4*3x*x

Wy multiply elements

12x^2*x

Wy multiply elements

12x^3

We do not support expression: x^3

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