(4-x)/8=(7x-1)/3

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Solution for (4-x)/8=(7x-1)/3 equation: 



(4-x)/8=(7x-1)/3

We move all terms to the left:

(4-x)/8-((7x-1)/3)=0

We add all the numbers together, and all the variables

(-1x+4)/8-((7x-1)/3)=0

We calculate fractions


(-x)/()+(-((7x-1)*8)/()=0



We calculate terms in parentheses: +(-((7x-1)*8)/(), so:

-((7x-1)*8)/(

We multiply all the terms by the denominator


-((7x-1)*8)



We calculate terms in parentheses: -((7x-1)*8), so:

(7x-1)*8

We multiply parentheses

56x-8

Back to the equation:

-(56x-8)



We get rid of parentheses

-56x+8

Back to the equation:

+(-56x+8)



We add all the numbers together, and all the variables

(-1x)/()+(-56x+8)=0

We get rid of parentheses

(-1x)/()-56x+8=0

We multiply all the terms by the denominator


(-1x)-56x*()+8*()=0

We add all the numbers together, and all the variables

(-1x)-56x*()=0

We get rid of parentheses

-1x-56x*()=0

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